(-2(5x^2-10x+10)+(10x-10))=0

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Solution for (-2(5x^2-10x+10)+(10x-10))=0 equation: 



(-2(5x^2-10x+10)+(10x-10))=0



We calculate terms in parentheses: +(-2(5x^2-10x+10)+(10x-10)), so:

-2(5x^2-10x+10)+(10x-10)

We multiply parentheses

-10x^2+20x+(10x-10)-20

We get rid of parentheses

-10x^2+20x+10x-10-20

We add all the numbers together, and all the variables

-10x^2+30x-30

Back to the equation:

+(-10x^2+30x-30)



We get rid of parentheses

-10x^2+30x-30=0

a = -10; b = 30; c = -30;
Δ = b2-4ac
Δ = 302-4·(-10)·(-30)
Δ = -300
Delta is less than zero, so there is no solution for the equation

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